R5.07-2A14
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-21.png)
R4.07-1A14
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-158.png)
R3.01-1A14
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-331.png)
解答
R4.07-1A14
3 1.5[A] 9[W]
ワンポイント解説
①コレクタ電流の最大値\(I_{cm1}=\frac{V}{R_L}\)
②最大電力\(P_{m0}=\frac{V^2}{2R_L}\)
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-21.png)
①コレクタ電流の最大値\(I_{cm1}=\frac{V}{R_L}=\frac{12}{8}=1.5\)[A]
②最大電力\(P_{m0}=\frac{V^2}{2R_L}=\frac{12^2}{2×8}=\frac{144}{16}=9\)[W]
R4.07-1A14
3 2[A] 16[W]
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-158.png)
①コレクタ電流の最大値\(I_{cm1}=\frac{V}{R_L}=\frac{16}{8}=2\)[A]
②最大電力\(P_{m0}=\frac{V^2}{2R_L}=\frac{16^2}{2×8}=\frac{256}{16}=16\)[W]
R3.01-1A14
5 3[A] 18[W]
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-331.png)
①コレクタ電流の最大値\(I_{cm1}=\frac{V}{R_L}=\frac{12}{4}=3\)[A]
②最大電力\(P_{m0}=\frac{V^2}{2R_L}=\frac{12^2}{2×4}=\frac{144}{8}=18\)[W]
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