R5.01-1A7
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-67.png)
R4.01-1A7
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-205.png)
R3.07-2A8
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-236.png)
R2.11-1A7
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-379.png)
H31.01-1A8
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-463.png)
解答
R5.01-1A7
\(5 \frac{50}{π}\) 20 \(\frac{5}{2π}\)
ワンポイント解説
共振周波数\(f_0=\frac{1}{2π\sqrt{LC}}\)
尖鋭度\(Q=\frac{ω_OL}{R}=\frac{1}{ω_OCR}=\frac{f_0}{B}\)
帯域幅\(B=f2−f1=\frac{f_0}{Q}\)
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-67.png)
共振周波数\(f_0=\frac{1}{2π\sqrt{LC}}=\frac{1}{2π\sqrt{1m×0.1μ}}=\frac{1}{2π\sqrt{10^{-10}}}=\frac{10^5}{2π}=\frac{50}{π}×10^{3}[Hz]\)
尖鋭度\(Q=\frac{ω_OL}{R}=\frac{1}{ω_OCR}=\frac{f_0}{B}=\frac{2πf_0L}{R}=\frac{2π\frac{50}{π}k×1m}{5}=20\)
帯域幅\(B=f2−f1=\frac{f_0}{Q}=\frac{\frac{50}{π}k}{20}=\frac{5}{2π}×10^3[Hz]\)
R4.01-1A7
\(1 1,250 5π \frac{250}{π}\)
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-205.png)
共振周波数\(f_0=\frac{1}{2π\sqrt{LC}}=\frac{1}{2π\sqrt{4m×\frac{40}{π^2}μ}}=\frac{1}{2π×\frac{1}{π}\sqrt{4^2×10^{-8}}}=\frac{1}{8×10^{-4}}=\frac{10,000}{8}=1,250[Hz]\)
尖鋭度\(Q=\frac{ω_OL}{R}=\frac{1}{ω_OCR}=\frac{f_0}{B}=\frac{2πf_0L}{R}=\frac{2π×1,250×4m}{2}=5π\)
帯域幅\(B=f2−f1=\frac{f_0}{Q}=\frac{1,250}{5π}=\frac{250}{π}[Hz]\)
R3.07-2A8
\(2 \frac{50}{π}\) 50 \(\frac{1}{π}\)
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-236.png)
共振周波数\(f_0=\frac{1}{2π\sqrt{LC}}=\frac{1}{2π\sqrt{1m×0.1μ}}=\frac{1}{2π\sqrt{10^{-10}}}=\frac{10^5}{2π}=\frac{50}{π}×10^{3}[Hz]\)
尖鋭度\(Q=\frac{ω_OL}{R}=\frac{1}{ω_OCR}=\frac{f_0}{B}=\frac{2πf_0L}{R}=\frac{2π\frac{50}{π}k×1m}{2}=50\)
帯域幅\(B=f2−f1=\frac{f_0}{Q}=\frac{\frac{50}{π}k}{50}=\frac{1}{π}[kHz]\)
R2.11-1A7
\(5 20π \frac{5}{π}\)[kHz]
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-379.png)
共振周波数\(f_0=100[kHz]\)
尖鋭度\(Q=\frac{ω_OL}{R}=\frac{1}{ω_OCR}=\frac{f_0}{B}=\frac{2πf_0L}{R}=\frac{2π×100k×1m}{10}=20π\)
帯域幅\(B=f2−f1=\frac{f_0}{Q}=\frac{100k}{20π}=\frac{5}{π}[kHz]\)
H31.01-1A8
\(5 \frac{50}{π}[kHz]\) 50 \(\frac{1}{π}[kHz]\)
![](https://miyabisazanka.com/wp-content/uploads/2023/08/image-463.png)
共振周波数\(f_0=\frac{1}{2π\sqrt{LC}}=\frac{1}{2π\sqrt{1m×0.1μ}}=\frac{1}{2π\sqrt{10^{-10}}}=\frac{10^5}{2π}=\frac{50}{π}×10^{3}=\frac{50}{π}[kHz]\)
尖鋭度\(Q=\frac{ω_OL}{R}=\frac{1}{ω_OCR}=\frac{f_0}{B}=\frac{2πf_0L}{R}=\frac{2π\frac{50}{π}k×1m}{2}=50\)
帯域幅\(B=f2−f1=\frac{f_0}{Q}=\frac{\frac{50}{π}k}{50}=\frac{1}{π}[kHz]\)
検索用キーワード
直列共振回路 図に示す直列共振回路について述べたものである。 コイル及びコンデンサには損失は無いものとする。 共振周波数 尖鋭度 共振曲線の半値幅
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